Question:

$29.5\, mg$ of an organic compound containing nitrogen was digested according to Kjeldahl?s method and the evolved ammonia was absorbed in $20\, mL$ of $0.1\, M\, HCl$ solution. The excess of the acid required $15 \,mL$ of $0.1\, M\, NaOH$ solution for complete neutralization. The percentage of nitrogen in the compound is

Updated On: Jun 23, 2023
  • 59
  • 47.4
  • 23.7
  • 29.5
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The Correct Option is C

Solution and Explanation

Moles of HCl reacting with ammonia = (moles of HCl absorbed ) - (moles of NaOH solution required) $= (20 \times 0.1 \times 10^{-3}) - (15 \times 0.1 \times 10^{-3})$ = moles of $NH_3$ evolved. = moles of nitrogen in organic compound $\therefore$ wt. of nitrogen in org. comp $= 0.5 \times 10^{-3} \times 14$ $= 7\times 10^{-3}\,g$ $\% wt = \frac{7\times 10^{-3}}{29.5\times 10^{-3}} = 23.7\%$
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