2-Bromobutane to but-2-ene
To convert 2-bromobutane into but-2-ene, an elimination reaction (E2 mechanism) is used. This reaction requires a strong base like potassium hydroxide (KOH).
In the E2 reaction, the base abstracts a proton from the β-carbon (the carbon adjacent to the one bonded to the bromine), and the bromine atom leaves simultaneously, resulting in the formation of a double bond (alkene).
\( \text{CH}_3\text{-CHBr-CH}_2\text{-CH}_3 \xrightarrow{\text{alc. KOH, heat}} \text{CH}_3\text{-CH=CH-CH}_3 \)
Product: But-2-ene (major product due to Zaitsev’s rule, which favors the more substituted alkene).
An object has moved through a distance can it have zero displacement if yes support your answer with an example.
Acidified \(KMnO_4\) oxidizes sulphite to:
The correct IUPAC name of \([ \text{Pt}(\text{NH}_3)_2\text{Cl}_2 ]^{2+} \) is:
Consider the following compounds:
(i) CH₃CH₂Br
(ii) CH₃CH₂CH₂Br
(iii) CH₃CH₂CH₂CH₂Br
Arrange the compounds in the increasing order of their boiling points.
Alkyl halides undergoing nucleophilic bimolecular substitution reaction involve: