Question:

2-Bromobutane to but-2-ene

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An E2 elimination mechanism involves the simultaneous removal of a proton and a leaving group, resulting in the formation of an alkene.
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Solution and Explanation

To convert 2-bromobutane to but-2-ene, you can use a strong base like potassium hydroxide (KOH) in an elimination reaction (E2 mechanism). This will remove the hydrogen atom from the carbon adjacent to the one bearing the bromine, resulting in the formation of the alkene. \[ \text{CH}_3\text{CHBrCH}_3 \xrightarrow{\text{KOH}} \text{CH}_3\text{CH=CH}_2 \] 

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