2-Bromobutane to but-2-ene
To convert 2-bromobutane into but-2-ene, an elimination reaction (E2 mechanism) is used. This reaction requires a strong base like potassium hydroxide (KOH).
In the E2 reaction, the base abstracts a proton from the β-carbon (the carbon adjacent to the one bonded to the bromine), and the bromine atom leaves simultaneously, resulting in the formation of a double bond (alkene).
\( \text{CH}_3\text{-CHBr-CH}_2\text{-CH}_3 \xrightarrow{\text{alc. KOH, heat}} \text{CH}_3\text{-CH=CH-CH}_3 \)
Product: But-2-ene (major product due to Zaitsev’s rule, which favors the more substituted alkene).
If vector \( \mathbf{a} = 3 \hat{i} + 2 \hat{j} - \hat{k} \) \text{ and } \( \mathbf{b} = \hat{i} - \hat{j} + \hat{k} \), then which of the following is correct?