Distance \((D)\) = Speed \((S)\) \(\times\)Time \((T)\)
\(D\) \(=4\times(T+\frac{15}{60})\)
\(D\) \(=4T+1\) …..(i)
\(D\) \(6(T-\frac{10}{60})\)
\(D\) \(=6T-1\) (ii)
Solving equations (i) and (ii), we get
\(T=1h\)
\(D\) \(=4\times1+1=5km\)
The correct option is (B)